SOLUTION: Container A,of volume a , is half full.Container B,of volume b,is one third full.container C,of volume c,is empty.If all the water in the containers is divided equally among the co

Question 603262: Container A,of volume a , is half full.Container B,of volume b,is one third full.container C,of volume c,is empty.If all the water in the containers is divided equally among the containers,What part of container C will be full? Please show me the steps.
A. (a+4b)/6c
B.(2a+b)/24c
C.(3a+2b)/18c
D.(6a+3b)/15c
E. none of these
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Container A, of volume a, is half full.
Container B, of volume b, is one third full.
container C, of volume c, is empty.
If all the water in the containers is divided equally among the containers,What part of container C will be full?
:
the total amt of water
a + b + 0c
:
Divide the total amt by 3
(a + b) = a + b
:
Container C fractional part full

Get rid of the fractions, multiply by
*() =
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