SOLUTION: Hi, I need help as soon as possible with a question about areas and volumes of similar solids. Im not even sure how to start out, because the examples aren't helping me much. So he

Question 599848: Hi, I need help as soon as possible with a question about areas and volumes of similar solids. Im not even sure how to start out, because the examples aren't helping me much. So here's the question:
A cylinder 4 in. in diameter and 6 in. high holds 1 lb of oatmeal. To the nearest ounce, how much oatmeal will a similar 10 in. high cylinder hold?(hint: 1 lb = 16 oz)
First, I tried to put the numbers in proportions such as 4 over the unknown diameter, and 6 in. over 10 in. to find the unknown diameter. The answer I got was 6.6666 and so on, but Im not sure if Im supposed to leave it like that, round it, or leave it as a mixed fraction.
After that, how do I calculate how much oatmeal is in the higher cylinder? I would like it if it can be explained to me clearly because this kind of problem confuses me.
I really hope someone can help me soon on this problem. Thank you!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A cylinder 4 in. in diameter and 6 in. high holds 1 lb of oatmeal. To the nearest ounce, how much oatmeal will a similar 10 in. high cylinder hold?(hint: 1 lb = 16 oz)
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Volume of the cylinder: Base*height
= (pi)r^2*h = 16(pi)*6 = 96(pi) cubic inches.
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Note: That volume holds 1 lb of oatmeal.
----------
how much oatmeal will a similar 10 in. high cylinder hold?(hint: 1 lb = 16 oz)
Volume = 16(pi)*10 = 160(pi) cu inches
-------
# of lbs. of oatmeal in the larger cylinder = [160(pi)]/(96(pi))
= 1 2/3 lbs = 1 lb 10 2/3 ounces
=====================================
Cheers,
Stan H.
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