SOLUTION: The internal and external diameters of a hollow hemisherical vessel are 14cm and 21cm respectively.The cost of silver plating of 1cm^2 of its surface is Rs 1.60.Find the total cost
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Question 550146: The internal and external diameters of a hollow hemisherical vessel are 14cm and 21cm respectively.The cost of silver plating of 1cm^2 of its surface is Rs 1.60.Find the total cost of siver plating the vessel all over.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Surface Area of hemisphere = 2pir^2
Outside sphere radius = 10.5 (21/2)
Outside surface area = 2*pi*10.5^2
692.72 cm^2
=
Inner radius = 7 (14/2)
Inner surface area = 2 * pi^7^2
=307.87 cm^2
Total surface area =1000.59 cm^2
You have to add the rim area
internal radius = 7 cm
outer radius = 10.5
Area of rim = pi* (10.5^2-7^2)
=192.42 cm^2
Total = 692.72+307.87 192.42
=1193.01 cm^2
1193.01* 1.6=Rs.1908.81
m.ananth@hotmail.ca
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