SOLUTION: (14y+8y^2+y^3+12)÷(6+y)
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Question 311188: (14y+8y^2+y^3+12)÷(6+y)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
First factor
Subtracted from the original polynomial gives a remainder of,
Second factor
Subtracted from the previous remainder gives a new remainder of,
Third factor:
Subtracted from the previous remainder gives a remainder of 0.
Gather up all of the factors.
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