SOLUTION: a 19 liter mixture consists by volume of one part juice, to 18 parts water. if x liters of juice and y liters of water are added to this mixture to make 54 liter mixture consisting

Question 262572: a 19 liter mixture consists by volume of one part juice, to 18 parts water. if x liters of juice and y liters of water are added to this mixture to make 54 liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a 19 liter mixture consists by volume of one part juice, to 18 parts water.
if x liters of juice and y liters of water are added to this mixture to make 54
liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x?
:
You see the original mixture had 1 liter of juice and 18 liters of water
:
=
Cross multiply
2(x+1) = y + 18
2x + 2 = y + 18
2x = y + 18 - 2
2x = y + 16
:
We know resulting amt was 19 liters and resulting amt is to be 54 liters
Therefore
x + y = 54 - 19
x + y = 35
y = (35-x)
;
Substitute (35-x) for y in the equation 2x = y + 16
2x = (35-x) + 16
2x + x = 35 + 16
3x = 51
x =
x = 17 liters of juice
and
y = 35-17
y = 18 liters of water
;
:
Check:
= = 1/2
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