SOLUTION: Silver metal has a density of 10.5g/cm^3. A solid sphere of silver has mass of 0.295 g. What is the diameter of the silver piece, in mm? The volume of a sphere is V= (4/3)3.14*r^

Algebra ->  Volume -> SOLUTION: Silver metal has a density of 10.5g/cm^3. A solid sphere of silver has mass of 0.295 g. What is the diameter of the silver piece, in mm? The volume of a sphere is V= (4/3)3.14*r^      Log On


   

Question 207749: Silver metal has a density of 10.5g/cm^3. A solid sphere of silver has mass of 0.295 g. What is the diameter of the silver piece, in mm? The volume of a sphere is V= (4/3)3.14*r^3 . I do not even know where to start with this.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You are given the density of silver and told about a silver sphere that has a mass of 0.295g.
So you need to find the diameter of a sphere that with that mass.
First let's figure out what volume the sphere must be.
10.5g%2F%28cm%5E3%29+=+0.295g%2F%28VolumeofSphere%29
VolumeOfSphere+=+0.295%2F10.5+=+0.0280952%28cm%5E3%29
You are asked to find the sphere's diamter in mm. So let's convert the volume to (mm)^3
There are 10 mm/cm, so the converion from (mm)^3/(cm)^3 = 10*10*10 = 1000(mm)^3/(cm)^3
VolumeOfSphere+=+1000%2A.0280952+=+28.0952%28mm%29%5E3
You are ready ro solve
%284%2F3%29%2Api%2Ar%5E3+=+28.0952
r%5E3+=+%2828.0952%2A3%29%2F%284+%2A+pi%29
Now just grind out the value for r.
Once you have that, you need to remember you were asked for the diameter. So just double the radius and you are there.