SOLUTION: Find the area of the shaded portion of the circle. Use 3.14 for π. Figure not drawn to scale.
The figure is an uncircumscribed circle with a square in it that says 10cm i
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Question 204056: Find the area of the shaded portion of the circle. Use 3.14 for π. Figure not drawn to scale.
The figure is an uncircumscribed circle with a square in it that says 10cm inside the square.The shaded portion is everything outside of the square, so portions of(in) the circle. I do not know if this question can be answered without the figure, but I have tried to figure this out and I have given up, it is over my head. Or if you could just give an example of an uncircumscribed circle and the shaded portion, would be helpful also. Thank you very much for your time.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find the area of the shaded portion of the circle. Use 3.14 for π. Figure not drawn to scale.
The figure is an uncircumscribed circle with a square in it that says 10cm inside the square.The shaded portion is everything outside of the square, so portions of(in) the circle. I do not know if this question can be answered without the figure, but I have tried to figure this out and I have given up, it is over my head. Or if you could just give an example of an uncircumscribed circle and the shaded portion, would be helpful also. Thank you very much for your time
:
From the given information, I understand that it is a square that fits exactly
inside the circle, the 10 cm is the diagonal of the square and would also be
the diameter of the circle, if this is correct here's how to do it:
Find the area of the circle
A = pi*r^2
Remember r = 10/2 = 5 cm
A = 3.14 * 5^2
A = 3.14 * 25
A = 78.5 sq/cm is the area of the circle
:
The diagonal of the square is also 10 cm, find the area of the square by
finding the length of the side of the square, call it x:
Using pythag a^2 + b^2 = c^2
a & b = x (it's a square)
c = 10
:
x^2 + x^2 = 10^2
2x^2 = 100
Remember x^2 = is also the area of the square
x^2 =
x^2 = 50 sq/cm is the area of the square
:
Circle area - square area
78.5 - 50 = 28.5 sq/cm is the area outside the square
:
:
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