SOLUTION: The Great Pyramid of Cheops has a square base of 771 ft on a side and a height of 486 ft. How many apartments 35 ft x 20 ft x 8 ft would be needed to have a volume equivalent to

Question 194006: The Great Pyramid of Cheops has a square base of 771 ft on
a side and a height of 486 ft. How many apartments 35 ft x
20 ft x 8 ft would be needed to have a volume equivalent to
that of the Great Pyramid�s
we need help again please
Found 2 solutions by checkley77, solver91311:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
771*771*486/3=96,299,442 FT^3 IS THE VOLUME OF THE PYRAMID.
35*20*8=5,600 FT^3 FOR EACH APARTMENT.
96,299,442/5,600=17,196 APARTMENTS EQUAL TO VOLUME OF THE PYRAMID.

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

where s is the measure of the side of the base and h is the measure of the height. Step 1, plug in your given numbers and calculate the volume of the pyramid. Step 2, calculate the volume of one 35 X 20 X 8 apartment. Divide the results of Step 1 by the results of Step 2. Round down to the nearest integer.

John

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