SOLUTION: who+many+briks+each+of+size+23cm+11.5+cm+8+cm+will+be+required+to+build+a+wall+of+size+11.5+meter+into+2.3+meter+into+40+cm

Algebra ->  Volume -> SOLUTION: who+many+briks+each+of+size+23cm+11.5+cm+8+cm+will+be+required+to+build+a+wall+of+size+11.5+meter+into+2.3+meter+into+40+cm      Log On


   

Question 1062412: who+many+briks+each+of+size+23cm+11.5+cm+8+cm+will+be+required+to+build+a+wall+of+size+11.5+meter+into+2.3+meter+into+40+cm
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
8 cm fits 40/8=5 times into 40 cm.
11.5 cm fits 1150/11.5=100 times into 11.5m=1150cm.
23 cm fits 230/23=10 times into 2.3m=230cm.
Used that way,
5%2A100%2A10=5000 bricks would be used.