SOLUTION: A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the

Question 1036005: A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the same and double the radius. What will be the affect on the can's volume?
Found 2 solutions by stanbon, Aldorozos:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the same and double the radius. What will be the affect on the can's volume?
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Original can DATA
Volume = pi*r^2*h
83 = pi*3^2*h
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New design DATA
V = pi*(2*3)^2*h
Rearrange::
V = pi*3^2*2^2*h
V = pi(3^2)h *2^2
V = 83*4
Ans:: The volume will be multiplied by 4.
Cheers,
Stan H.
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Answer by Aldorozos(172) (Show Source): You can put this solution on YOUR website!
Let's reword the problem. If we change the radius from 3 inches to 6 inches and keep the height the same, what will be effect on the cans volume?
The volume of the first can is Pi*r^2*h = pi*9*h
The volume of the sec. can is pi*R^2*h = pi*36*h
If we divide sec. by first we will have 36/9 = 4
This means that the volume is 4 times bigger. The trick to this problem is that we didn't need the volume of 83 cubic inches to do this calculation. This means that the problem has given us additional information that we didn't need.
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