SOLUTION: find the value of x that minimises y=18x^2+(100/x) for positive x. 1. In order to do that first find the derivative dy/dx 2. How many critical numbers does y have, for posit

Question 1033171: find the value of x that minimises y=18x^2+(100/x) for positive x.

1. In order to do that first find the derivative dy/dx
2. How many critical numbers does y have, for positive x ?
3. What is the nature of the critical number of the previous part?
4. give the exact value of the x that minimises y for positive x?
5. Now give the value approximately as a two place decimal.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
1.

2.
One
3. Nature?
4.

5. I leave that to you.

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