SOLUTION: find the position vector for PQ if P=(-2,3) and Q=(14,-2)

Question 638511: find the position vector for PQ if P=(-2,3) and Q=(14,-2)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the position vector for PQ if P=(-2,3) and Q=(14,-2)
------
length = sqrt[(-2-3)^2+(14--2)^2] = sqrt[25+256] = sqrt(281) = 16.76
-----------------
tangent of angle = -5/16
tan^-1(-5/16) = -17.35 degrees
-----
Position vector extends from (0,0) to (5,-16)
or, in polar form (16.76,-17.36)
---------------------
Cheers,
Stan H.
RELATED QUESTIONS
The lines l and m have vector equations r = 2i-j+4k+s(i+j- k) and r= -2i + 2j+ k+... (answered by Timnewman)

If p,q>0, log base p of q+ log base qof p=5/2 and pq=54√ 2, then find... (answered by greenestamps)

PLEASE HELP ME PLEASE IF ANYONE CAN IF(P-Q)^2=25 AND PQ=14,WHAT IS THE VALUE OF... (answered by josgarithmetic)

If P=(-2,0) Q=(10,-14) and R=(-4, -2), is PQ=QR, using the distance... (answered by Alan3354)

P(-2,3), Q(8,-5) ... PQ = sqr164 and midpoint of PQ is sqr41; Find coordinates of R (x,... (answered by MathLover1,greenestamps)

The lines l and m have vector equations r = 2i-j+4k+s(i+j- k) and r= -2i + 2j+ k+... (answered by math_tutor2020)

Given that p and q are the roots of the quadratic equation 2x^2+2px=q^2,if p-q=6 find the (answered by robertb,josmiceli)

The lines l and m have vector equations r = 2i-j+4k+s(i+j- k) and r= -2i + 2j+ k+... (answered by ElectricPavlov)

If P=x+1/x-1 and Q=x-1/x+1, find... (answered by khwang)