Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

h(x)=x^2-6x+9    |Completing the Square

h(x)=(x-3)^2 -9 +9

h(x)= (x-3)^2     |a = 1 >0, parabola open Upward 

Vertex(-3,0) also the x-intercept

y-intecept h(x) = 9, when x = 0

always recommend graphing or 'picturing' the graph in Your mind.



 

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