# SOLUTION: what is the magnitude U: magnitude 1,850, bearing 125 degrees V: magnitude 2,960, bearing 25 degrees W: U+V

Algebra ->  Algebra  -> Vectors -> SOLUTION: what is the magnitude U: magnitude 1,850, bearing 125 degrees V: magnitude 2,960, bearing 25 degrees W: U+V      Log On

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 Algebra: Introduction to vectors, addition and scaling Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Vectors Question 43408: what is the magnitude U: magnitude 1,850, bearing 125 degrees V: magnitude 2,960, bearing 25 degrees W: U+VAnswer by fractalier(2101)   (Show Source): You can put this solution on YOUR website!The process of adding or subtracting vectors involving breaking the pieces down into their horizontal and vertical components first...then combining like components...then changing the components into polar form...for this one we have...I use q and p for theta and phi... Ux = U cos q = 1850 cos 125° = -1061 Uy = U sin q = 1850 sin 125° = 1515 Vx = V cos p = 2960 cos 25° = 2683 Vy = V sin p = 2960 sin 25° = 1251 now add 'em Wx = Ux + Vx = -1061 + 2683 = 1622 Wy = Uy + Vy = 1515 + 1251 = 2766 now r = sqrt(x^2 + y^2) and theta = arctan(y/x) so that r = sqrt(1622^2 + 2766^2) = 3206 and theta = arctan(2766/1622) = 59.6° and finally (whew!) W = magnitude 3206, bearing 59.6° Study this example carefully because I probably won't do this kind of problem again...