SOLUTION: find the center of the circle defined by the equation 2x^2+2y^2+24x+28y+138=0. I'm kinda confused on how to start solving this problem, please help.

Question 372682: find the center of the circle defined by the equation 2x^2+2y^2+24x+28y+138=0.
I'm kinda confused on how to start solving this problem, please help.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square in and .

Compare to the general equation for a circle centered at (,) with a radius :

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