SOLUTION: Differentiate the function. Do not expand any expression before differentiating: a) f(x)=[(2-x)^4+16]^3 b) f(x)=1/((x^2)-16)^5

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Question 183715: Differentiate the function. Do not expand any expression before differentiating:
a) f(x)=[(2-x)^4+16]^3
b) f(x)=1/((x^2)-16)^5

Answer by stanbon(57225) About Me  (Show Source):
You can put this solution on YOUR website!
Differentiate the function. Do not expand any expression before differentiating:
Use the chain rule as follows:
a) f(x)=[(2-x)^4+16]^3
f'(x) = 3[(2-x)^4+16]^2 * 4(2-x)^3 * (-1)
---------------------
b) f(x)=1/((x^2)-16)^5
f(x) = ((x^2)-16)^-5
f'(x) = -5[((x^2)-16)^-4]
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Cheers,
Stan H.