# SOLUTION: Differentiate the function. Do not expand any expression before differentiating: a) f(x)=[(2-x)^4+16]^3 b) f(x)=1/((x^2)-16)^5

Algebra ->  Algebra  -> Vectors -> SOLUTION: Differentiate the function. Do not expand any expression before differentiating: a) f(x)=[(2-x)^4+16]^3 b) f(x)=1/((x^2)-16)^5       Log On

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 Algebra: Introduction to vectors, addition and scaling Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Vectors Question 183715: Differentiate the function. Do not expand any expression before differentiating: a) f(x)=[(2-x)^4+16]^3 b) f(x)=1/((x^2)-16)^5 Answer by stanbon(57225)   (Show Source): You can put this solution on YOUR website!Differentiate the function. Do not expand any expression before differentiating: Use the chain rule as follows: a) f(x)=[(2-x)^4+16]^3 f'(x) = 3[(2-x)^4+16]^2 * 4(2-x)^3 * (-1) --------------------- b) f(x)=1/((x^2)-16)^5 f(x) = ((x^2)-16)^-5 f'(x) = -5[((x^2)-16)^-4] =================================== Cheers, Stan H.