SOLUTION: Find the slope of the tangent to the curve at the given point: f(x)=(√16-x), where y=5

Algebra ->  Algebra  -> Vectors -> SOLUTION: Find the slope of the tangent to the curve at the given point: f(x)=(√16-x), where y=5      Log On

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Question 180732: Find the slope of the tangent to the curve at the given point:
f(x)=(√16-x), where y=5
Answer by Alan3354(21583) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the tangent to the curve at the given point:
f(x)=(√16-x), where y=5
------------------
y+=+%2816-x%29%5E%281%2F2%29
@y=5:
5+=+%2816-x%29%5E%281%2F2%29
25 = 16-x
x = -9
---------------
dy%2Fdx+=+%281%2F2%29%2A%2816-x%29%5E%28-1%2F2%29%2A%28-1%29
@x = -9:
y' = (-1/2)/5
y' = -1/10