SOLUTION: Find the value(s) of x at which the functions are discontinuous. Show how, thanks! b.) g(x)=7x-4/x c.) ((x^2)-1)/x^3 e.) g(x)=13x/((x^2)+x-6)

Algebra ->  Algebra  -> Vectors -> SOLUTION: Find the value(s) of x at which the functions are discontinuous. Show how, thanks! b.) g(x)=7x-4/x c.) ((x^2)-1)/x^3 e.) g(x)=13x/((x^2)+x-6)       Log On

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Question 179640: Find the value(s) of x at which the functions are discontinuous. Show how, thanks!
b.) g(x)=7x-4/x
c.) ((x^2)-1)/x^3
e.) g(x)=13x/((x^2)+x-6)

Answer by Fombitz(13823) About Me  (Show Source):
You can put this solution on YOUR website!
You can graph the functions and look for regions that go from infinity to -infinity or vice versa.
These specific functions are discontinuous (undefined) any time the denominator goes to zero.
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b)At x=0.
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+graph%28+300%2C+300%2C+-5%2C+5%2C+-10%2C+10%2C+%287x-4%29%2Fx%29+
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c)At x=0.
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+graph%28+300%2C+300%2C+-5%2C+5%2C+-10%2C+10%2C+%28%28x%5E2%29-1%29%2Fx%5E3%0D%0A%29+
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d) When x^2+x-6=0,
x%5E2%2Bx-6=0
%28x%2B3%29%28x-2%29=0
At x=-3 and at x-2.
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+graph%28+300%2C+300%2C+-5%2C+5%2C+-10%2C+10%2C+%2813x%29%2F%28%28x%5E2%29%2Bx-6%29%29%0D%0A+
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