SOLUTION: Greetings, I am currently in Physical Science and right off the bat we started on vectors, motion, and Newtons Law. Anyway, I haven't been in a College atmosphere in quite a while

Question 155178This question is from textbook The Physical Universe
: Greetings, I am currently in Physical Science and right off the bat we started on vectors, motion, and Newtons Law. Anyway, I haven't been in a College atmosphere in quite a while. So I need some serious help!!! This will sound silly yet I for some reason can not get it. Here it is: Two cars leave a cross roads at the same time. One heads north at 50Km/h and the other heads east at 70Km/h. How far apart are the cars after 2 hours? This question is from textbook The Physical Universe

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
The car headed north at 50 km/hr will have traveled a distance of 100km after 2 hours, right? ((2hrs)*(50km/hr) = 100km.
The car headed east at 70 km/hr will have traveled 140km after 2 hours, ok? (2hrs)*(70km/hr) = 140km.
So you now have two legs of a right triangle in which the base is a vector of magnitude 140km and the height is a vector of magnitude 100km.
The distance between the two cars, after 2 hours of travel, is represented by the hypotenuse of this right triangle.
So you can call upon Pythagoras to help find the length (distance vector) of the hypotenuse (d).

km. Approximately.
This would be a vector whose magnitude is 172.

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