SOLUTION: A 5-ton truck moving at a constant speed of 20 m/s takes a turn around a circular path with a radius of 50 m. Find the acceleration and the net force on the truck.

Algebra.Com
Question 1175339: A 5-ton truck moving at a constant speed of 20 m/s takes a turn around a circular path with a radius of 50 m. Find the acceleration and the net force on the truck.
Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.

I will assume that you use the metric system consistently in this problem, so 5 ton means 5000 kilograms of mass.

    To find the centripetal acceleration, use the formula  a =  ,

    where v is the linear velocity (in m/s) and r is the radius of the circle (in meters).



    To find the net force, multiply the mass of 5000 kg by the centripetal acceleration.


    You will get the force in newtons.


If you need an authoritative source, look into this Wikipedia article

https://en.wikipedia.org/wiki/Circular_motion#:~:text=Consider%20a%20body%20of%20one,second%2C%20which%20is%20one%20newton.



RELATED QUESTIONS

An object is moving in a circular path with a radius of 40 cm at a speed of 4 m/s.... (answered by KMST)
While following a circular path of radius 8.0 m a truck requires a centripetal... (answered by nyc_function)
A centripetal force of 150 N acts on a 1,100-kg satellite moving with a speed of 5,100... (answered by ikleyn)
A particle is moving around in a circle of radius R = 1.5 m with a constant speed of 2... (answered by ikleyn)
While walking between gates at an airport, you notice a child running along a moving... (answered by lwsshak3)
a circular ground of radius 7 m has a path of width 7 m around it on its outside. the... (answered by Cromlix)
A race car goes around a circular level track with a diameter of 1.00 km at a constant... (answered by ikleyn)
How much centripetal force is needed to keep a 0.2 kg ball on a 1.50 m long string moving (answered by ikleyn)
How much centripetal force is needed to keep a 0.38 kg ball on a 1.55 m string moving in... (answered by addingup,MathLover1)