From x =, you get, squaring, x^2 = , x^2*(t+1) = 1 x^2*t + x^2 = 1 x^2*t = 1 - x^2 t = . Now substitute it into the expression for y = . You will get y = : = : = 1- x^2. So, the curve is the parabola y = 1- x^2. ANSWER
Hi x(t)= 1/√t+1 and y(t)=t/t+1 t ≠ -1 x^2 = 1/(t+1) 0r (t+1) = 1/x^2 0r t = 1/x^2 -1 substituteWish You the Best in your Studies.