SOLUTION: Please help! (multiple choice) A box with weight 48 N is on a rough horizontal surface. An external force F is applied horizontally to the box. A normal force and a friction for

Question 1162033: Please help! (multiple choice)
A box with weight 48 N is on a rough horizontal surface. An external force F is applied horizontally to the box. A normal force and a friction force are also present, denoted by n and f. When force F equals 8.4 N, the box is in motion at constant velocity. When force F equals 10.92 N, the acceleration of the box is closest to:
A) 0.70 m/s2
B) 0.51 m/s2
C) 0.79 m/s2
D) 0.61 m/s2
E) 0.88 m/s2

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Hint: Since Force equals mass times acceleration, if acceleration is zero, net force must be zero. Hence, the applied force and the friction force must be equal when the applied force is 8.4 N. Then then net force when the applied force is 10.92 N, must be 2.52 N.

John

My calculator said it, I believe it, that settles it

RELATED QUESTIONS
Please help? (Multiple Choice) A 9.6 kg box is held at rest by two ropes that form... (answered by ikleyn)

A horizontal force of 250 N is applied to a stationary wooden Box in one direction and a... (answered by ikleyn)

A box weighing 543 N is at rest on a ramp at an angle of 15o with the horizontal. The... (answered by Fombitz)

A box weighing 543 N is at rest on a ramp at an angle of 15 with the horizontal. The... (answered by Fombitz)

Two blocks of masses 5 kg and 7 kg are placed in contact with each other on a... (answered by solver91311)

he coefficient of static and kinetic frictions between a 3.0-kg box and a desk are 0.40 (answered by ikleyn)

Please help! "A woman takes her dog Rover for a walk on a leash. To get the little... (answered by solver91311,Alan3354)

Blocky has a mass of 22 kg, and is sitting on a horizontal, frictionless arena. A force... (answered by solver91311)

A steady 50 N horizontal force is applied to a 10 kg object on a table. The object... (answered by CubeyThePenguin)