SOLUTION: A 10 kg box is resting on a ramp inclined at 35° to the horizontal. Resolve the weight of the box into the rectangular vector components that keep the box at rest. Include a diagr

Question 1159990: A 10 kg box is resting on a ramp inclined at 35° to the horizontal. Resolve the weight of the box into the rectangular vector components that keep the box at rest. Include a diagram illustrating this situation.
Found 2 solutions by ikleyn, MowMow:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

The components of the weight are W*sin(a) = 10*sin(35°) = 10*0.5733 kilograms = 5.733 kilograms = 5.733*9.81 newtons = 56.243 newtons PARALLEL the incline and W*cos(a) = 10*cos(35°) = 10*0.8193 kilograms = 8.193 kilograms = 8.193*9.81 newtons = 80.376 newtons PERPENDICULAR to the incline.

Solved.

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Notice that kilograms are not used as the unit of weight (of force) since sixties
last century, been replaced by Newtons.

So your source is EXTREMELY outdated.

The numbers by @MowMow are incorrect (!)

Avoid use it (!)

@MowMow, you need seriously update/refresh your knowledge (!) (!)

Had I calculate forces for engineering projects at my positions here in US, as you do in your post,
I would be fired next day.

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Regarding a diagram, open any textbook in Physics and find a diagram there.

Or look into the lesson
    - Using vectors to solve problems in Mechanics: Force, Figures 3, 4 and 5
in this site.

Answer by MowMow(42)   (Show Source): You can put this solution on YOUR website!
Fv = 10Cos(55) and Fh = Fh/10 = Sin(35)

The box is kept at rest by a force of 5.74 N perpendicular to the ramp and by a friction of 8.19N parallel to the ramp
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