SOLUTION: Find three cube roots for the complex number. Leave your answers in trig form. In degrees, not cis form 8(cos 90 + i sin 90) W0 = W1= W2=?

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Question 1080026: Find three cube roots for the complex number. Leave your answers in trig form. In degrees, not cis form 8(cos 90 + i sin 90) W0 = W1= W2=?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
W0 = 2*(cos(30) + i*sin(30)).


W1 = 2*(cos(150) + i*sin(150)).     Notice that 150 = 30 + 120 = 30 + .


W1 = 2*(cos(270) + i*sin(270)).     Notice that 270 = 30 + 2*120 = 30 + .


There is a bunch of lessons on complex numbers
    - Complex numbers and arithmetical operations on them
    - Complex plane
    - Addition and subtraction of complex numbers in complex plane
    - Multiplication and division of complex numbers in complex plane
    - Raising a complex number to an integer power
    - How to take a root of a complex number (*)
    - Solution of the quadratic equation with real coefficients on complex domain
    - How to take a square root of a complex number
    - Solution of the quadratic equation with complex coefficients on complex domain

    - Solved problems on taking roots of complex numbers (*)
    - Solved problems on arithmetic operations on complex numbers
    - Solved problem on taking square root of complex number
in this site.


In this list, the lessons marked by (*) specially relate to taking roots of high degree of complex numbers.
So, these lessons specially relate to your problem.


Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Complex numbers".



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find three cube roots for the complex number. Leave your answers in trig form. In degrees, not cis form 8(cos 90 + i sin 90)
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Change to trig form if you like.

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