The position vector of OP, OQ and OR is <0,0,0>, <1,2,3> and <2,1,-1> respectively. Find
i) the area of the triangle PQR
The cross product is the area of the parallelogram,
and so the area of the triangle is half that.
The area is ∥OQ×OR∥/2 = = ∥-5i+7j-3k∥/2 =
We find the magnitude of vectors OQ and OR
∥OQ∥ =
∥OR∥ =
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ii) the projection of QR and OR
I think you meant "onto", not "and".
the projection of QR onto OR is given by
OQ•OR
projOROQ = ————— OR
∥OR∥²
OQ•OR = <1,2,3>•<2,1,-1> = (1)(2)+(2)(1)+(3)(-1) = 1
∥OR∥² = 2²+1²+(-1)² = 4+1+1 = 6
So,
projOROQ =
Edwin