Hi, I'm having trouble with the problem h(x) = -16x^2 + 64x + 140 where h(x) equals the height. I'm trying to find the height, but I'm not sure how to. When asked to write the quadratic function in vertex form I came up with f(x) = 16(x+2)^2-56.
Thanks.
The height is represented by the y-coordinate of the VERTEX
The height, or y-coordinate of the VERTEX, or h(x) occurs at: -----> ------> ------> x = 2
------- Substituting 2 for x
The height, or y-coordinate of the VERTEX occurs at h(2), and is:
It is that simple!
If you NEED to write the quad function in VERTEX form, then that's another story, but you don't have to!