SOLUTION: Hi, I'm having trouble with the problem h(x) = -16x^2 + 64x + 140 where h(x) equals the height. I'm trying to find the height, but I'm not sure how to. When asked to write the quad

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Question 1012194: Hi, I'm having trouble with the problem h(x) = -16x^2 + 64x + 140 where h(x) equals the height. I'm trying to find the height, but I'm not sure how to. When asked to write the quadratic function in vertex form I came up with f(x) = 16(x+2)^2-56.
Thanks.

Found 3 solutions by josgarithmetic, MathLover1, MathTherapy:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!
You should study how to use Completing the Square to change from general form to standard (or vertex) form. Your book should discuss this; otherwise study here: This lesson INCLUDES how to complete the square and put function into standard form.
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
in vertex form






vertex is at:
(, )




Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Hi, I'm having trouble with the problem h(x) = -16x^2 + 64x + 140 where h(x) equals the height. I'm trying to find the height, but I'm not sure how to. When asked to write the quadratic function in vertex form I came up with f(x) = 16(x+2)^2-56.
Thanks.
The height is represented by the y-coordinate of the VERTEX
The height, or y-coordinate of the VERTEX, or h(x) occurs at: -----> ------> ------> x = 2

------- Substituting 2 for x



The height, or y-coordinate of the VERTEX occurs at h(2), and is:
It is that simple!
If you NEED to write the quad function in VERTEX form, then that's another story, but you don't have to!
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