Questions on Algebra: Introduction to vectors, addition and scaling answered by real tutors!

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Question 88187: Find the magnitude of the following vector: v=4i-2j: Find the magnitude of the following vector: v=4i-2j
Answer by stanbon(18718) About Me  (Show Source):
You can put this solution on YOUR website!
Find the magnitude of the following vector: v=4i-2j
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r = sqrt(4^2 + (-2)^2)
r = sqrt(20)
r = 2sqrt5
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Cheers,
Stan H.
Question 88187: Find the magnitude of the following vector: v=4i-2j: Find the magnitude of the following vector: v=4i-2j
Answer by jim_thompson5910(9162) About Me  (Show Source):
You can put this solution on YOUR website!
To calculate the norm of the vector use the following formula:

where is the dot product of the given vector with itself

Remember the dot product of the vector with itself is:




Calculate the dot product of the radicand

Multiply

Add

Simplify if possible

So



Check:
Lets use Pythagorean's Theorem to check our work

Notice if we draw the vector we get
drawing(500, 500, -5+2, 5+2, -5+2, 5+2,<BR>
graph(500, 500, -5+2, 5+2, -5+2, 5+2, 0),<BR>
green(line(0,0,4,0)),<BR>
green(line(4,0,4,-2)),<BR>
arrow(0,0,4,-2)<BR>
) Plot of the vector (black line) with the vector components (green)
We can see that the vector has x and y components, which form the legs of the triangle. We can also see that the legs are 4 units and 2 units

Since we have a triangle with legs of 4 , 2 and a hypotenuse of x(our unknown side), we can use Pythagoreans theorem to find the unknown side.
Pythagoreans theorem
a^2+b^2=c^2

4^2+2^2=c^2 Plug in a=4 and b=2 and lets solve for c
1 6 + 4 =  c  ^ 2 Square each individual term



2 0 =  c  ^ 2 Combine like terms


s q r t ( 2 0 ) = s q r t (  c  ^ 2 ) Take the square root of both sides

2*sqrt(5)=c simplify

So the length of the hypotenuse is 2*sqrt(5). This verifies our answer