Questions on Algebra: Introduction to vectors, addition and scaling answered by real tutors!

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Question 117933:
If 3x^2-2x+7=0 then (x-1/3)^2=:
If 3x^2-2x+7=0 then (x-1/3)^2=
Answer by checkley71(8405) About Me  (Show Source):
You can put this solution on YOUR website!
THESE PROBLEMS DON'T NEED A CALCULATOR IF YOU KNOW HOW TO SOLVE SQUARE ROOTS, MULTIPLY & DIVIDE (LONG METHOD).
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3x^2-2x+7=0
using the quadratic equationx=(-b+-sqrt(b^2-4*a*c))/(2*a) we get:
x=(2+-sqrt[-2^2+4*3*7])/2*3
x=(2+-sqrt[4-84])/6
x=(2+-sqrt-80)/6
x=(2+-8.944i)/6
x=2/6-8.944i/6
x=1/3+1.49i answer.
x=1/3-1.49i answer.
then:
(x-1/3)^2=(1/3+1.49i-1/3)^2=(1.49i)^2=-2.22 answer.
or (x-1/3)^2=(1/3-1.49i-1/3)^2=(-1.49i)^2=-2.22 answer.