Tutors Answer Your Questions about Trigonometry-basics (FREE)
Question 61066: What is the advantage of helping students with their homework? What's in it for you guys? Are you simply pure philanthopic beings with the sole desire to help humanity, or is there a catch? I know I am being cynical, but there is no such thing as a free lunch.
Click here to see answer by rfadrogane(214)   |
Question 252388: 1) if the product (2x+3)(x+k)is 2x to the 2nd power + 13x+15 find the value of k
2)write a quadratic expression that is the difference of two squares.
3)factor 15m to the 4 power - 6m to the 2nd power + 9m
4)14x to the 5th power - 49x to the 8th power
5) subtract (-8x to the 4th power +3x)-(5x-4-x to the 4th power)
Click here to see answer by richwmiller(9144)  |
Question 251050: Heres 3 questions I was curious about
Given sin A = 1/3 A in Quad II, CosB = -3/5 B in Quad III,
find Sin(A+B) and tan2B
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Solve for x : 0 < or = x < or = 360
3cos^2x = cosx AND 3cos^2x - 5sinx = 1
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prove this identity:
sin2x/sinx - cos2x/cosx = secx
Click here to see answer by drk(1908) |
Question 252605: The height of the ocean at the dock is modeled by the function, h= 3sin(pi*t/4) +5 where h is measured in feet and t is the time in hours. If t=0 refers to 12:00 a.m., what is the height of the ocean at 10:00 a.m.?
find the exact value of the vertical asymptotes for 0<=x<=pi for the function y=cot(3x)
if sin(x)= -3/5 with x in the quadrant 4, find the sec(x)
Thanks so much!!
Click here to see answer by jim_thompson5910(28715) |
Question 252614: Can you help me solve this questions, please?
The original ferris wheel, designed by George Ferris, was 250 feet in diameter. Making 1 revolution for every 40 seconds, h(t)=125sin(0.157t -pi/2) +125 represents the height h (feet) of a seat on the wheel at any time t (seconds). The ride begins when t = 0. During the first 30 seconds of the ride, at what time is a rider on the ferris wheel exactly 125 feet above the ground?
and also, help me with:
approximate the solution to 2cosx+x=0 to the nearest hundredth.
Hints: it should be in radian mode and there are no () around the x+x
Thanks so much!!
Click here to see answer by jim_thompson5910(28715) |
Question 252614: Can you help me solve this questions, please?
The original ferris wheel, designed by George Ferris, was 250 feet in diameter. Making 1 revolution for every 40 seconds, h(t)=125sin(0.157t -pi/2) +125 represents the height h (feet) of a seat on the wheel at any time t (seconds). The ride begins when t = 0. During the first 30 seconds of the ride, at what time is a rider on the ferris wheel exactly 125 feet above the ground?
and also, help me with:
approximate the solution to 2cosx+x=0 to the nearest hundredth.
Hints: it should be in radian mode and there are no () around the x+x
Thanks so much!!
Click here to see answer by drk(1908) |
Question 253255: Could you please help me prove that sin(x+y)sin(x-y)=cos^2y-cos^2x?
This is what I have done so far...
sin(x+y)sin(x-y)can be changed to(sinxcosy+sinycosx)(sinxcosy-sinycosx)
Also, cos^2y-cos^2x can be changed to 1-sin^y-1-sin^2x
I'm not sure if I am going about this the right way, so if not, could you please point me in the right direction?
Click here to see answer by jim_thompson5910(28715) |
Question 253255: Could you please help me prove that sin(x+y)sin(x-y)=cos^2y-cos^2x?
This is what I have done so far...
sin(x+y)sin(x-y)can be changed to(sinxcosy+sinycosx)(sinxcosy-sinycosx)
Also, cos^2y-cos^2x can be changed to 1-sin^y-1-sin^2x
I'm not sure if I am going about this the right way, so if not, could you please point me in the right direction?
Click here to see answer by drk(1908) |
Question 253255: Could you please help me prove that sin(x+y)sin(x-y)=cos^2y-cos^2x?
This is what I have done so far...
sin(x+y)sin(x-y)can be changed to(sinxcosy+sinycosx)(sinxcosy-sinycosx)
Also, cos^2y-cos^2x can be changed to 1-sin^y-1-sin^2x
I'm not sure if I am going about this the right way, so if not, could you please point me in the right direction?
Click here to see answer by Greenfinch(383)  |
Question 253555: Hello, I was wondering if anyone could help me solve this problem:
If angles x and y are in the same quadrant, and sinx=3/5 and cosy=-5/13 determine the value of sin (x-y).
I would greatly appreciate the help!
Thanks,
Justine
Click here to see answer by drk(1908) |
Question 253571: Find a polynomial P(x) of degree 4 with zeros 2,2, 1-√3i, and with constant coefficient of 32.
Note: The third zero is one minus radical 3 times i. Which is an imaginary number known as radical negative one.
I am only given 3 zeros but I don't know the fourth zero! Can I assume the fourth zero is just x?
I tried doing the problem:
P(x)= 32 (x-2) (x-2) [x- (1-√3i)]
I got stuck from here. Please help me! Thank you for your time!
Click here to see answer by drk(1908) |
Question 253637: A radioactive substance has an initial mass of 100 grams and its mass halves every 4 years. Write an expression that shows the number of grams remaining after x years.
I tried doing this problem by following this formula:
initial mass times [1+ (r/n)]^nt
r= rate
n= number of 'stuff' I think it is the number of time periods which the substance halves. It should be expressed by t/4.
t= time
Since the problem is a decay model isn't the rate negative? So I believe it should be -0.5.
100 [1+((-0.5/(t/4))]^t/4*t
I just get stuck here because it becomes very hairy and confusing...
Click here to see answer by ankor@dixie-net.com(15746)  |
Question 253637: A radioactive substance has an initial mass of 100 grams and its mass halves every 4 years. Write an expression that shows the number of grams remaining after x years.
I tried doing this problem by following this formula:
initial mass times [1+ (r/n)]^nt
r= rate
n= number of 'stuff' I think it is the number of time periods which the substance halves. It should be expressed by t/4.
t= time
Since the problem is a decay model isn't the rate negative? So I believe it should be -0.5.
100 [1+((-0.5/(t/4))]^t/4*t
I just get stuck here because it becomes very hairy and confusing...
Click here to see answer by stanbon(57967) |
Question 253677: I need help with a very difficult math assignment i have recieved my math teachers makes it way more complicated then it has to be.
1.) if sin x= (12/13), cos y=(3/5) and x and y are acute angles, the value of cos(x-y) is
a.(21/65) b.(63-65) c. -(14/65) d. -(33/65)
2.) if the tangent of an angle is negative and its secant is positive, in which quadrant does the angle terminate
1,2,3 or 4 i thought it was the second quadrant but i dont understand the term terminate i wasnt sure if that ment the opposite of what it was.
Click here to see answer by drk(1908) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810
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