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Tutors Answer Your Questions about Trigonometry-basics (FREE)
Question 173043: I cant solve these problem's would like some help.
1.If cos 0= -4/5,find sec 0.
2.Find the value of sin 0 for angle 0 in standard position of the point (-2,-4)that lies on the terminal side.
3.Suppose 0 is an angle in standard position whose terminal side lies in quadrant 2 and the tan 0=-1.Find the remaining trigonometric functions for the function 0.
4.Use the right triangle ABC to find side a if A=37 and b=9''.
Click here to see answer by Alan3354(6153)  |
Question 173167: Please help me on my homework. I really need your help.
35. From a plane 2,000 m above sea level, the pilot observes two ships in line due west. The angles of depression of the two ships are 60 degrees and 70 degrees. How far apart are the ships?
36. A television antenna is situated atop a hill. From a point 200 m from the base of the cliff, the angle of elevation of the top of the antenna is 80 degrees. The angle of elevation of the bottom of the antenna from the same point is 75 degrees. How tall is the antenna?
37. A 40-cm long pendulum is moved 45 degrees from the vertical. How far did the tip of the pendulum rise?
38. Nuel travels due north from his house for 100 km, then 70 km due west, and then 60 km due north, then he stops. How far is he from from the house?
39. From the 3rd floor of a school building, one can see the top of a house at an angle of elevation of 40 degrees. If the place of observation is 20 m above the ground and 50 m from the house, how high is the house?
40. How long is the midline of an isosceles right triangle when its legs are 20-cm long?
Click here to see answer by Alan3354(6153)  |
Question 173390: Please help me verify this equation:
cscx - cscx
------ ------ =2sec^2x
1+cscx 1-cscx
yes, the cscx's are over 1+cscx and 1-cscx. Those are fractions.
So far i have gotten stuck on this porblem. i have expanded csc x into 1/sinx in both parts of the left side of the equation which gets me:
1/sinx - 1/sinx
-------- --------- = 2sec^2x
1+1/sinx 1-1/sinx
After that i tried to achieve a common denominator on the left side which is where i get lost. I'm not sure what step to do after that or how to solve it.
Click here to see answer by gonzo(654)  |
Question 173459: I do not understand these at all could use help.
Solving Triangle's
1.K=40and k=26.FindL,j and l.
2.j=65 and l=55. Find K,L and k.
3.Solve Triangle ABC.Round to the nearest tenth if necessary.A=30,B=45,and a=10
Click here to see answer by Alan3354(6153)  |
Question 172275: I have two questions. One of them I came up with an answer, but am not sure if it is right.
1. Find the esact value of: tan(-3pi)
2. Find the exact value of: sin60 degrees - cos60 degrees.
For this I came up with an answer of 0.366
I have to show all my work.
Thanks
Click here to see answer by Alan3354(6153)  |
Question 174276: I need help verifying this identity.
cot^2x-cos^2x = (cot^2x)(cos^2x)
So I tried:
(cos^2x)/(sin^2x) -cos^2 = (cos^2x)/(sin^2x)(cos^2x)
But after that I'm kind of stumped. Any help with future steps would be appreciated!
Thanks so much!
Click here to see answer by stanbon(26367)  |
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