SOLUTION: Solve the equation on the interval 0≤θ<2π.
2sinθ+4=5
What are the solutions in the interval 0≤θ<2π​?
what is the solution set?
Algebra.Com
Question 997025: Solve the equation on the interval 0≤θ<2π.
2sinθ+4=5
What are the solutions in the interval 0≤θ<2π?
what is the solution set?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Subtract 4 from both sides.
Divide both sides by 2.
or Use the unit circle to determine which angles correspond to points on the unit circle that have a y coordinate of
The solutions in the interval [0,2pi) are or
Solution set: 
RELATED QUESTIONS
What is sin^2 θ-1=0 using the interval 0 ≤ θ < 2 π?
(answered by Alan3354)
Solve the equation for 0 ≤ θ ≤ 2π.
cosθ - sinθ = 0 (answered by Fombitz)
what is cosθ= 1/root2 on the interval... (answered by Theo)
What is sin(2θ)sinθ=cosθ using the interval 0 ≤ θ < 2... (answered by Alan3354,lwsshak3)
Solve the following trigonometric equations over the interval... (answered by richard1234)
What is 2cos^2 θ + cosθ -1=0 using the interval 0 ≤ θ < 2 π?
(answered by lwsshak3)
Solve on 0≤ θ < 2 π, using a calculator, the equation θ cos... (answered by stanbon)
Find the number of solutions of tan^2θ + 1/4 = 0 on -π ≤ θ ≤... (answered by lwsshak3)
Without using a calculator, find all solutions to cos(θ)=−3√2 in the... (answered by solver91311)