SOLUTION: If sin A=3/5 then find (tan A+sec A)^2

Question 993633: If sin A=3/5 then find (tan A+sec A)^2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If sin A=3/5 then find (tan A+sec A)^2
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Since sin = y/r, y = 3 and r = 5
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Then, x = sqrt[5^2-3^2] = sqrt(16) = 4
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So, tan(A) = y/x = 3/4 and sec(A) = r/x = 5/4
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Ans: (tan(A)+sec(A))^2 = (3/4+5/4)^2 = 2^2 = 4
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Cheers,
Stan H.
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