SOLUTION: solve for x E[0,2pi] :2sin^2x-sinx=0

Question 992448: solve for x E[0,2pi] :2sin^2x-sinx=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve for x E[0,2pi] :
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2sin^2x-sinx=0
Factor::
sin(x)[2sinx-1] = 0
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sin(x) = 0 or sin(x) = 1/2
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x = 0 or x = pi/6 or x = (5/6)pi
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cheers,
Stan H.
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