SOLUTION: sen2x=-√3/2 tan3x=1 cosx/2=√3/2 cotx/3=-1/√3 senx/2+cosx=1 senx.cosx=1/2

Algebra ->  Trigonometry-basics -> SOLUTION: sen2x=-√3/2 tan3x=1 cosx/2=√3/2 cotx/3=-1/√3 senx/2+cosx=1 senx.cosx=1/2      Log On


   

Question 992186: sen2x=-√3/2
tan3x=1
cosx/2=√3/2
cotx/3=-1/√3
senx/2+cosx=1
senx.cosx=1/2
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Is this one problem? or 6?

Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.
You systematically write  senx,  which is,  probably,  sen(x).

In the standard school Math,  there is no such function,  senx / sen(x).

There is  sin(x),  which stands for sines.

Do not use  senx / sen(x)  in future.


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Comment from student: Sorry its LIN x
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