SOLUTION: sen2x=-√3/2
tan3x=1
cosx/2=√3/2
cotx/3=-1/√3
senx/2+cosx=1
senx.cosx=1/2
Algebra.Com
Question 992186: sen2x=-√3/2
tan3x=1
cosx/2=√3/2
cotx/3=-1/√3
senx/2+cosx=1
senx.cosx=1/2
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Is this one problem? or 6?
Answer by ikleyn(52834) (Show Source): You can put this solution on YOUR website!
.
You systematically write senx, which is, probably, sen(x).
In the standard school Math, there is no such function, senx / sen(x).
There is sin(x), which stands for sines.
Do not use senx / sen(x) in future.
------------------------------------------------
Comment from student: Sorry its LIN x
------------------------------------------------
Oo!! It looks like you have broken keyboard.
If you do not understand, here is one well known "programmer's joke":
"A kyboard for sal: only on ky dosn't work".
Ha-ha-ha.
Please do not write me more. Thank you.
RELATED QUESTIONS
√x-3 = √x+2 -... (answered by ankor@dixie-net.com)
√(2x+1)+√(x-3)=2 (answered by stanbon,MathTherapy,ikleyn)
Solve: 2√(1-x) - 3√(2x-1) =... (answered by josgarithmetic)
1-2cosx^2/sinx cosx =... (answered by Alan3354)
Solve the following.
1. 9∜7 + 8∜7 - 3∜7
2. 1/2 √2 + 1/2... (answered by lynnlo)
Multiply:
(5√[2] + 3)(√[2] – 2√[3])
(answered by stanbon,MathLover1)
Multiply:
(5√[2] + 3)(√[2] – 2√[3])
(answered by Fombitz)
Simplify... (answered by stanbon)
Prove using reciprocal and pythagorean identities: (cscx-cotx)/(secx-1)= cotx
I have... (answered by jsmallt9)