SOLUTION: At a time t,the horizontal path of an object is given by x==3+2t and the vertical height by y=(4t^3-4t-9t) (t-1)^-1

SOLUTION: At a time t,the horizontal path of an object is given by x==3+2t and the vertical height by y=(4t^3-4t-9t) (t-1)^-1

Algebra.Com

Question 990662: At a time t,the horizontal path of an object is given by x==3+2t and the vertical height by y=(4t^3-4t-9t) (t-1)^-1

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do you have a question?

RELATED QUESTIONS
The position of an object at time t is given by s(t) = 3 - 4t. Find the instantaneous... (answered by MathLover1)

{{{ (t^2-1)/(t^2-4) }}} + {{{ (9t+9)/(4t+12) }}} * {{{ (2-t)/(t^2+2t-3) }}} The back... (answered by Alan3354,greenestamps,MathTherapy)

Can you help me to solve the following question: The vertical displacement of the end... (answered by htmentor)

What is the set up to the word problem As a particle moves along a straight path, its... (answered by stanbon)

{{{ h(t) = c - (d-4t)^2 }}} At time t=0, a ball was thrown upward from an initial... (answered by ikleyn)

1.An object moves along a straight path whose distance from the reference point is given... (answered by Boreal)

h(t)=c-(d-4t)(d-4t) At time t=0, a ball was thrown upward from an initial height of 6... (answered by richwmiller)

An object is thrown straight up into the air then follows a trajectory , the height... (answered by ikleyn)

Solve: (2t + 1)^3 = (2t + 1) My solution: (2t + 1)^3 / (2t + 1) = (2t + 1) / (2t +... (answered by richwmiller)