SOLUTION: Given that sin 64° = 9/10 and cos 64° = (√19)/10 find the following:
1. cot 64° =
2. cos -64° =
3. csc 64° =
4. csc -26° =
5. sec 244° =
Algebra.Com
Question 990134: Given that sin 64° = 9/10 and cos 64° = (√19)/10 find the following:
1. cot 64° =
2. cos -64° =
3. csc 64° =
4. csc -26° =
5. sec 244° =
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
sin(64) is not 9/10
RELATED QUESTIONS
Evaluate if possible 3√ - 64 [cube root of -64] and 3√ 64 [cube root of 64]... (answered by Alan3354)
Find the other five trigonometric functions for each of the following given:
1. sin ¢ =... (answered by Alan3354)
Just not getting this.
Suppose cos t = -0.4 and csc t < 0 . Find each of the following (answered by lwsshak3)
URGENT HELP NEEDED PLEASE HELP..!
Use the Data to answer the questions
Stem ---... (answered by stanbon)
Find the sum of -16 + 4 - 1 + ...
Does not exist
64/5
-64/5... (answered by fractalier)
please help me. this is my last resort
1. Find the midpoint and... (answered by Fombitz)
1/64^-4/3 (answered by ikleyn)
Sin=3/5
Cot=1
Sec=7/2
Cos=9/40
Tan=√3... (answered by ikleyn)
Identify the type of equation 0 = 3x2 + y2 – 12x – 30y + 181.
parabola
circle
ellipse
(answered by richard1234)