SOLUTION: solving 2tan^2(theta)sin(theta)-tan^2(theta)=0 for all values in [0,360)

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Question 987184: solving 2tan^2(theta)sin(theta)-tan^2(theta)=0 for all values in [0,360)
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
2tanē(q)sin(q) - tanē(q) = 0
    tanē(q)[2sin(q) - 1] = 0

tanē(q) = 0;   2sin(q) - 1 = 0
q = 0°, 180°;      2sin(q) = 1
                    sin(q) = 1/2
                         q = 30°, 150°

Edwin
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