SOLUTION: Could you help mi figure out the value of a in the following formula SecA + CscA = 3 solve for angle a, and please include work

Question 986738: Could you help mi figure out the value of a in the following formula
SecA + CscA = 3
solve for angle a, and please include work
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
SecA + CscA = 3
solve for angle a
==============
(1/cos) + (1/sin) = 3
(sin + cos)/sin*cos = 3
sin + cos = 3sin*cos
Square both sides
sin^2 + 2sin*cos + cos^2 = 9sin^2cos^2
cos^2 = 1 - sin^2
sin^2 + 2sin*cos + 1 - sin^2 = 9sin^2(1 - sin^2) = 9sin^2 - 9sin^4
2sin*cos + 1 = 9sin^2 - 9sin^4
2sin*cos + sin^2 + cos^2 = 9sin^2 - 9sin^4
===========================
I see no option other than graphical or iterative methods.
=============================
A =~0.59045279001103
A =~0.98034353678387
A =~2.890976773032889
A =~4.963004860941594
-------------------------
It's periodic, period of 2pi

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