SOLUTION: I have been working on this problem and feel kind of stuck:
----------- ---
"Consider a triangle ABC.
Suppose that sides a=63, b=51, and c=16.
Solve the triangle.
Carry yo
Algebra.Com
Question 985964: I have been working on this problem and feel kind of stuck:
---------------
"Consider a triangle ABC.
Suppose that sides a=63, b=51, and c=16.
Solve the triangle.
Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.
If there is more than one solution, use the OR button."
---------------
When I try to break it down using the Inverse Cosine, I keep getting NaN. Not sure if I am doing it wrong or if it is actually No Solution.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I have been working on this problem and feel kind of stuck:
---------------
"Consider a triangle ABC.
Suppose that sides a=63, b=51, and c=16.
Solve the triangle.
Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.
If there is more than one solution, use the OR button."
---------------
When I try to break it down using the Inverse Cosine, I keep getting NaN. Not sure if I am doing it wrong or if it is actually No Solution.
==============================================
IDK what NaN means. Sodium Nitrogen?
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Use the Cosine Law to find an angle.
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c^2 = a^2 + b^2 - 2ab*cos(C)
16^2 = 63^2 + 51^2 - 2*63*51*cos(C)
cos(C) = -6314/-6426 =~ 0.982571
C =~ 10.71295 degs
---------------
Then use either the Cosine Law of the Law of Sines to find a 2nd angle.
---
The 3rd angle = 180 - (angle1 + angle2)
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