SOLUTION: Please solve the equation for the interval [0, 2pi]: {{{2sin^2(x)-sin(x)-1=0}}} Thank you!

SOLUTION: Please solve the equation for the interval [0, 2pi]: {{{2sin^2(x)-sin(x)-1=0}}} Thank you!

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Question 983736: Please solve the equation for the interval [0, 2pi]:

Thank you!
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Temporarily make a substitution, v=sin(x).

OR

Go from those. Solution is based on one of the simple reference angles.
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