SOLUTION: prove that 1/1+sinx - 1/1-sinx = -2sinx sec^2x
Ive only managed to do this:
LHS
= 1/1+sinx - 1/1-sinx
=1-sinx/1-sin^2x - 1+sinx/1-sin^2x
=-2sinx/1-sin^2x
=-2sinx/cos^2x
Algebra.Com
Question 983428: prove that 1/1+sinx - 1/1-sinx = -2sinx sec^2x
Ive only managed to do this:
LHS
= 1/1+sinx - 1/1-sinx
=1-sinx/1-sin^2x - 1+sinx/1-sin^2x
=-2sinx/1-sin^2x
=-2sinx/cos^2x
and i got stuck there
Answer by ikleyn(52817) (Show Source): You can put this solution on YOUR website!
You are absolutely right with yours transformations.
The only thing you need to add to it is the equality
= ,
which is simply the definition of , and then
= ,
which is the consequence of the definition.
Good luck !
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