SOLUTION: What are the cube roots of {{{(1/2-(sqrt(3)/2) *i)}}}? (Answer using cis(x) notation where x is assumed to be in degrees.) Do not include the degree symbol in your answers.

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Question 983323: What are the cube roots of ?
(Answer using cis(x) notation where x is assumed to be in degrees.)
Do not include the degree symbol in your answers.
P.S. In the original problem to sqrt(3)/2 does not have a parentheses around it.
Thank you in advanced.

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!

= cos(-60) + i*sin(-60) = cos(300) + i*sin(300)       (the angles are in degrees).

Three complex cubic roots of this number are

1.  cos(100) + i*sin(100)       (100 = ).

2.  cos(100+120) + i*sin(100+120) = cos(220) + i*sin(220)       (120 = )

3.  cos(100 + 240) + i*sin(100+240) = cos(340) + i*sin(340)

See my lessons on complex numbers in this site  REVIEW of lessons on complex numbers  and especially the lesson  How to take a root of a complex number.


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