SOLUTION: Please use the remainder theorem to evaluate {{{4x^3 - 3x^2 + 2x - 3 when x=2}}}

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Question 981966: Please use the remainder theorem to evaluate
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
This means, use synthetic division with "root to check" being 2 and dividend . The remainder will be the given expression (your dividend) evaluated for x=2.

Do you need to see the work?
response: YES.

Root to check on the left, dividend coefficients on the other side of the "vertical wall". This shows a start setup of the synthetic division:
___________________________________________
___________|
______2____|_____4______-3______2_______-3
___________|
___________|_________________________________


___________________________________________
___________|
______2____|_____4______-3______2_______-3
___________|____________8_______10______24
___________|_________________________________
_________________4_______5______12_______21

The remainder is 21;
this means that 4x^3 - 3x^2 + 2x - 3 will be 21 for x=2.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Please use the remainder theorem to evaluate
Since , then remainder when x = 2 is:

f(2) = 4(8) - 3(4) + 4 - 3
f(x) = 32 - 12 + 4 - 3
(Remainder)
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