SOLUTION: A tightrope walker is about to cross a rope from a dock to the bridge of a boat that is 1.5m above the level of the dock. The rope is 15m long. At what angle of inclination will th

Question 980117: A tightrope walker is about to cross a rope from a dock to the bridge of a boat that is 1.5m above the level of the dock. The rope is 15m long. At what angle of inclination will the tightrope walker be climbing?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Consider that this is a right
angled triangle.
Distance up to bridge = 1.5m
This is the opposite side
Rope length = 15m
This is the hypotenuse
Angle of inclination = x
sinx = opposite/hypotenuse
sinx = 1.5/15
sinx = 0.1
sin^-1x = 5.74 degrees (2 decimal places)
Hope this helps:-)
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