SOLUTION: (1) Why is (cosx-sinx)^2 = to 1-2sinxcosx? That's the answer the prof. gave but I don't get that :/

Algebra.Com
Question 978214: (1) Why is (cosx-sinx)^2 = to 1-2sinxcosx?
That's the answer the prof. gave but I don't get that :/

Answer by josgarithmetic(39631)   (Show Source): You can put this solution on YOUR website!


Most basic of trigonometric identities,

DONE

RELATED QUESTIONS

Solve the eq on the interval [0,2pi) : sin2x-cosx=0 I used the indetity sin2x =... (answered by solver91311,Alan3354)
prove that left side equation is equal to the right side 1+cosx/1-cosx + 1-sinx/1+sinx = (answered by Aswathy)
I need to verify that the equation is an identity. {{{(sinx-cosx)^2=1-sin2x}}} I... (answered by scott8148)
Use lim(x goes to 0) sinx/x = 1 to evaluate lim(x goes to 0) 1-cosx/x^2. I know the... (answered by solver91311)
(2sinxcosx + cosx - 2sinx - 1)/(-sin(squared)x) = (2 sinx + 1)/(cosx+1) Please prove one (answered by kev82)
Add and simplify {{{cosx/sinx+sinx/cosx}}} My teacher informed my class that the... (answered by Alan3354)
Please help me solve this problem! If cosx = 1/5. Find all possible values of secx -... (answered by advanced_Learner)
Sketch sinx and its inverse on the same set of axes for 0≤ x ≤ (pi/2) I sketched... (answered by Theo,math_tutor2020)
(sqrt2)(sinx)(cosx)+(cosx)=0 Cosx(sqrt2*sinx+1)=0 cosx(sqrt2*sinx+1)^2=0 Where do... (answered by Alan3354)