SOLUTION: Hi All ,
I'm confused on this problem how to add the following vectors:
A=352, Angle A=174 degrees and B=276, Angle B=388 degrees
Can you please help me solve this and show me
Algebra.Com
Question 978037: Hi All ,
I'm confused on this problem how to add the following vectors:
A=352, Angle A=174 degrees and B=276, Angle B=388 degrees
Can you please help me solve this and show me step by step how to work it? Thanks!
Found 2 solutions by Alan3354, rothauserc:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A=352, Angle A=174 degrees and B=276, Angle B=388 degrees
Can you please help me solve this and show me step by step how to work it?
---------------
388 degrees?
confirm angle B
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
we are given the polar coordinates of two vectors A and B, the first step is to convert them into Cartesian coordinates
*******************************************************************
measure angle direction from x axis, 174 = -6 and 388 = 28
Vector A
x = r * cos(theta) = 352 * cos(-6) = 350.07170717 approx 350.07
y = r * sin(theta) = 352 * sin(-6) = -36.79401907 approx -36.79
********************************************************************
Vector B
x = r * cos(theta) = 276 * cos(28) = 243.693535629 approx 243.69
y = r * sin(theta) = 276 * sin(28) = 129.574151329 approx 129.57
********************************************************************
now add them
(350.07, -36.79) + (243.69, 129.57) = (593.76, 92.78)
magnitude(C) = square root(593.76^2 + 92.78^2)
C = 600.965112132 approx 600.97
tan (thetaC) = 92.78 / 593.76 = 0.156258421
inverse tan (0.156258421) = 8.881130134 approx 9 degrees
*******************************************************************
therefore,
vector sum is (593.76, 92.78)
vector component magnitude is 600.97 and direction is 9 degrees
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