SOLUTION: let a be the root of the equation
25cos^2a + 5 cos a - 12=0 where, pie/2<a<pie then what is tan a equal to?
Algebra.Com
Question 976405: let a be the root of the equation
25cos^2a + 5 cos a - 12=0 where, pie/2
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
25cosa^2 + 5cosa - 12 = 0
(5cosa - 3)(5cosa + 4) = 0
cos a = 3/5 = 0.6
53.1 degs, 306.9 degs
or
cos a = -4/5 = -0.8
143.1 degs , 216.9 degs
Hope this helps:-)
RELATED QUESTIONS
FInd the exact value of tan(A-B) if cos(A)=3/5 where 0< or equal to A (answered by lwsshak3)
7. Suppose sin a= -4/5 where 3pie/2 (answered by Alan3354)
Let alpha be the arc such that: alpha belongs to ] pie over 2, pie[ and cos alpha= -12... (answered by Alan3354,math_tutor2020)
What are the values that satisfy the trigonometric equation for 0 <= q <= 2? sin(theta) + (answered by jsmallt9)
2cos(5 theta) + square root of 3 = 0
I have tried making theta equal 5theta and... (answered by lwsshak3)
sorry, these problems aren't from a textbook. I've started these four problems then just... (answered by Edwin McCravy)
if tan A = 4/3 and tan B=12/5.find cos (A-B)
given 0<... (answered by Fombitz)
if tan A = 4/3 and tan B=12/5. find cos (A-B)
given 0< A < B <... (answered by Theo)
if sin alpha = 1/ square root 5 , 0< alpha < pie by 2,. find the exact values of
a)... (answered by jsmallt9)