SOLUTION: Find all solutions of the equation in the interval [0,2pi) 2sinØ - (square root 3)= 0

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Question 976340: Find all solutions of the equation in the interval [0,2pi)
2sinØ - (square root 3)= 0
Answer by lwsshak3(11628) About Me  (Show Source):
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Find all solutions of the equation in the interval [0,2pi)
2sinØ - (square root 3)= 0
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2sinØ-√3=0
sinØ=√3/2
Ø=π/3, 2π/3 (In quadrants I and II where sin>0)