SOLUTION: Find all solutions of the equation in the interval [0,2pi) 2sin� - (square root 3)= 0

SOLUTION: Find all solutions of the equation in the interval [0,2pi) 2sin� - (square root 3)= 0

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Question 976340: Find all solutions of the equation in the interval [0,2pi)
2sin� - (square root 3)= 0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find all solutions of the equation in the interval [0,2pi)
2sin� - (square root 3)= 0
***
2sin�-√3=0
sin�=√3/2
�=π/3, 2π/3 (In quadrants I and II where sin>0)
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